Department of Chemistry, Pondicherry University

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Welcome to Online learning and teaching site of Department of Chemistry, Pondicherry University. Access your course material 24x7. Submit assignments, takes tests and examinations online. Interact with course tutors/mentors, and fellow classmates in real time. Monitor your progress, check course tutor feedback and many more.

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1. Login (top right corner) with your @chempu.ac.in mail id. You will be taken to microsoft's login page (office 365) for login confirmation and will be redirected to this site after successful login

2. The front dashboard will display all your enrolled courses. Alternatively, you may also visit https://classwork.chempu.ac.in/my/

Whom to contact for support?

Send mail to admin@chempu.ac.in or venkatesanr@chempu.ac.in

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Summation Formula:

Constant Series

\begin{equation}
\sum_{k=0}^{S} c=s c
\end{equation}

Example: If S = 4

\begin{equation}
\begin{array}{c}{\sum_{k=0}^{4} c=0+c+c+c+c=4 c} \\ {\sum_{k=0}^{4} c=4 c}\end{array}
\end{equation}

Linear Series: \begin{equation}
\sum_{k=0}^{S} k=\frac{S(S+1)}{2}
\end{equation}

Example: If S = 4 \begin{equation}
\begin{array}{c}{\sum_{k=0}^{4} k=0+1+2+3+4=10} \\ {\sum_{k=0}^{S} k=\frac{S(S+1)}{2}=10}\end{array}
\end{equation}

Quadratic Series

\begin{equation}
\sum_{k=0}^{S} k^{2}=\frac{S(S+1)(2 S+1)}{6}
\end{equation}

Example if S = 4 \begin{equation}
\begin{array}{l}{0^{2}+1^{2}+2^{2}+3^{2}+4^{2}=0+1+4+9+16=30} \\ {\sum_{k=0}^{4} k^{2}=\frac{4(4+1)(2 \times 4+1)}{6}=\frac{4 \times 5 \times 9}{6}=30}\end{array}
\end{equation}

Roos of Quadratic Equation

If, \begin{equation}
a x^{2}+b x+c=0
\end{equation}

then, \begin{equation}
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}
\end{equation}

Binomial Expansion

\begin{equation}
(1+x)^{n}=1+n x+\frac{n(n-1)}{2 !} x^{2}+\frac{n(n-1)(n-2)}{3 !} x^{3}+\ldots \ldots \ldots \ldots \ldots
\end{equation}

To compute \((a+b)^{n}\)

\begin{equation}
(a+b)^{n}=a^{n}(1+x)^{n}, \quad \text { with } x=\frac{b}{a}
\end{equation} or \begin{equation}
\circ(a+b)^{n}=b^{n}(1+y)^{n}, \quad \text { with } y=\frac{a}{b}
\end{equation}

\begin{equation}
(a+x)^{n}=\sum_{k=0}^{n}\left(\begin{array}{c}{n} \\ {k}\end{array}\right) x^{k} a^{n-k},\left(\begin{array}{c}{n} \\ {k}\end{array}\right)=\frac{n !}{k !(n-k) !}
\end{equation}

\begin{equation}
(1+r)^{-1}=1-r+r^{2}-r^{3}+\cdots
\end{equation}

\begin{equation}
a\left(\frac{1-r^{n}}{1-r}\right)=a+a r+a r^{2}+a r^{3}+\cdots
\end{equation}

\begin{equation}
\sum y^{i}=1+y+y^{2}+\cdots \cdots=\frac{1}{1-y},(y<1)
\end{equation}

\begin{equation}
\sum i y^{i}=y\left(1+2 y+3 y^{2}+\cdots \cdots\right)=\frac{y}{(1-y)^{2}},(y<1)
\end{equation}

Trigonometric Formula

to continue...

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The chemical structure below is generated on the fly from 'Chemaxon Smiles' format

Steps to create the chemical structures

1. Visit: https://marvinjs-demo.chemaxon.com/latest/demo.html

Draw the molecule/reaction of your choice using drawing tools.

Marvin Drawing Windows

2. After completing your drawing, click save button (marked as 1 in figure below) and a new window will pop-up to select ChemAxon Smiles format from the dopdownbox (marked as 2 in figure below)

Marvin Drawing Save

3. Select the content and use Ctrl+c to copy the text. This defines the structure of your molecule

Marvin Drawing Save

4. You can now insert this string inside course contents/activities/questions/resources anywhere using the following special html format

Drawing Marvin

Note the copied Smiles format is enclosed between two 'chem' tags. Note the beginning and end tag formats. You should not change this markup format.

When the document is displayed the image will appear as

The image produced with a default dimension of 200px by 200px

5. You can change the size of the image by adding them after the string like below

Drawing Marvin

please note the '@w' for width description and '@h' for height description separator and you should not use any other separator. The first number represents width and second represents height of the image